Find angle 1, angle 2, and angle 3

61° , 151° , 12°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180° , then

∠ 1 + 29° + 90° = 180°

∠ 1 + 119° = 180° ( subtract 119° from both sides )

∠ 1 = 61°

∠ 2 and 29° are adjacent angles on a straight line and sum to 180° , then

∠ 2 + 29° = 180° ( subtract 29° from both sides )

∠ 2 = 151°

Using sum of angles in a triangle = 180°

∠ 3 + 17° + 151° = 180°

∠ 3 + 168° = 180° ( subtract 168° from both sides )

∠ 3 = 12°

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet