Suppose we wish to find an upper bound for R 2 0 cos x 2 dx. Explain why we cannot doing so using only a left Riemann sum or only a right Riemann sum on the interval [0, 2]. (b) How can we adapt the ideas in the sample solution to develop a method that will give an upper bound for R 2 0 cos x 2 dx

after simplifying it i got: -36.25 as my answer. hope that !

so, converting firstly the mixed fractions to improper fractions and then "adding".

step-by-step explanation:

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =