Use the information in the table to answer each question. Interval Value of
f(x)
(−∞, −2)
Positive
(−2, 1)
Negative
(1, 3)
Negative
(3, ∞)
Positive
(a)
What are the three real zeros of the polynomial function f? (Enter your answers as a comma-separated list.)
x =

answer: 5100 just subtract

step-by-step explanation:

y=sec x is the correct answer

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1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

answer: the actual answer is a. good bank will have the least amount in fees per year.