If -3x - 7y = -5 is a true equation, what would be the value of -12x – 28y?

-20

Step-by-step explanation:

-3x - 7y = -5

Multiply each side by 4

4(-3x - 7y) = -5*4

-12x -28y = -20

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< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐