What is the equation of the given circle? A. (x - 3)² + (y + 2)² = 1
B. (x+3)^2 +(y-2)^2= 2
c. (x+3)^2 +(y – 2)^2 = 1
D. (x-3)^2 + (y + 2)^2 = 2

6e14 is the answer.

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

the answer would be  

a.

3: 1

step-by-step explanation: