4. Graph the area bounded by y < 1/2x+6, x+3y>12, x > 0, and X < 12. Part I: Graph the area bounded by x > 0 and x < 12. Shade the region that satisfies both inequalities.

Part II: To the graph you already produced, add the region bounded by the lines y < 1/2x+6 and
x+3y > 12. Shade the region that satisfies both of these inequalities and the inequalities from Part 1

mia khalifa

step-by-step explanation:

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x

4+3x is the answer

hope you got it

what am i trying to find out. you didn't put up the whole question.

step-by-step explanation: