Evaluate \dfrac{3}{2}+(-k)+(-2)23+(−k)+(−2)s tart fraction, 3, divided by, 2, end fraction, plus, left parenthesis, minus, k, right parenthesis, plus, left parenthesis, minus, 2, right parenthesis where k = -\dfrac{5}{2}k=−25k, equals, minus, start fraction, 5, divided by, 2, end fraction.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

kk.bj.

step-by-step explanation:

.mnm.kn.kj