How do I solve this :
3x + y= 1 and x - 2y = 5

(1,-2)

Step-by-step explanation:

x - 2y = 5

3x + y= 1 (1)

x - 2y = 5

x = 5 + 2y (2)

Substitute (2) into (1)

3x + y = 1

3(5 + 2y) +y = 1

15 + 6y + y = 1

15 + 7y = 1

7y = 1 - 15

7y = -14

y = -2  (3)

Plug (3) into (1) to find x

3x + y = 1

3x + (-2) = 1

3x - 2 = 1

3x = 3

x = 1

(1,-2)

i believe it's a.

i'm not sure on this one, most likely correct.

yes, i think so although i am not sure. this is a very strange question.