The equation Y-5 = 6(x+1) is written in point-slope form. What is the equation written in slope-intercept form? O y = 6x + 11
O y = 6x - 1
O y = 6x - 4
O y = 6x + 6.

Option A: y = 6x + 11

Step-by-step explanation:

Given the linear equation in point-slope form, y - 5 = 6(x + 1), and that we must determine its equivalent slope-intercept form, y = mx + b:

First, we must distribute 6 into the parenthesis on the right-hand side of the equation:

y - 5 = 6(x + 1)

y - 5 = 6x + 6

Lastly, we must add 5 to both sides of the equation to isolate y:

y - 5 + 5 = 6x + 6 + 5

y = 6x + 11

Therefore, the slope-intercept form is: y = 6x + 11, which matches Option A.

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: