Find the value of 'y' if 27^y = 9/3^y.
Help me please..

y = 1/2.

Step-by-step explanation:

Note that 27 = 3^3 and 9 = 3^2:

27^y

= (3^3)^y

= 3^3y.

9/3^y

= 3^2/3^y

= 3^(2-y)

So 3^3y = 3^(2-y)

and therefore:

3y = 2 - y

4y = 2

y = 1/2.

Given that:

27^y = 9/3^y

⇛27^y × 3^y = 9

⇛(3^3)^y × 3^y = 9

⇛3^3y × 3^y = 9 [°.° (a^m)^n = a^mn]

⇛3^(3y+y) = 9 [°.° a^m×a^n = a^m+n]

⇛3^(4y) = 9

⇛3^(4y) = 3^2 [Bases equal ⇛exponents to equal]

.°. 4y = 2

y = 2:4 = 1/2

Hence, the value of y is 1/2.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3