Ejercicio 2: Supongamos que se tiene un recipiente cilíndrico de radio y altura lleno de un líquido de densidad constante y que se desea vaciar el contenido llevando el líquido a la parte superior del recipiente. Calcula el trabajo que se requiere para llevar a cabo esta tarea, realizando los pasos que se te piden. Ayuda: Para calcular el trabajo para vaciar el recipiente se puede pensar en seccionar el contenido del recipiente en un número infinito de elementos cilíndricos de radio y anchura (ver figura inferior) y calcular el trabajo que se tiene que realizar para llevar cada una de estas secciones a la parte superior del recipiente.

a) Calcula el diferencial de volumen de uno de estos elementos cilíndricos de anchura .



b) Calcula el diferencial de masa correspondiente.



c) Calcula el diferencial de peso correspondiente.

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy