A satellite orbits Earth 5.00x10^2 km above its surface. What is its period? The radius of Earth is 6.38x10^6 m and Earth has a mass of 5.97x10^24 kg.
Assume (G = 6.67x10^-11).

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step-by-step explanation:

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step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet