ABCD is a parallelogram and X and Y are any point on CD and AD respectively. Prove that triangle AXB and triangle BYC are equal in area. Prove that

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Step-by-step explanation:

ABCD is a parallelogram                     Given

BC ≅ AD; AB ≅ DC                             opposite sides of a parallelogram ≅

Δ AXB = 1/2 (AB)(AD)                           Formula for the area of a Δ

Δ BYC = 1/2 (BC) (DC)                           Formula for the area of a Δ

1/2 (AB)(AD)= 1/2(BC)(DC)                      Substitution

∴ Area of Δ AXB = Area of ΔBYC

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50