What is the smallest 9 digit number of the form aaa, aaa, aaa such that it is divisible by 9? (Notice that all the digits of this number must be the same!)

The smallest 9 digit number is 100000000,. As it is based on the concept that smallest two digit number is 10, three 100, four 1000 and so on.

Step-by-step explanation:

idk lol

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct