Please show the steps you use :) What are the coordinates of the vertex for f(x) = 3x^2 + 6x + 3? (1 point)

Group of answer choices

(−1, 0)

(3, 6)

(0, −1)

(6, 3)

vertex = (- 1, 0 )

Step-by-step explanation:

Given a parabola in standard form

f(x) = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = -

f(x) = 3x² + 6x + 3 ← is in standard form

with a = 3, b = 6 , then

= - = - 1

Substitute x = - 1 into f(x) for corresponding y- coordinate of vertex

f(- 1) = 3(- 1)² + 6(- 1) + 3 = 3(1) - 6 + 3 = 3 - 6 + 3 = 0

vertex = (- 1, 0 )

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.

option a is correct.

step-by-step explanation:

scale factor: it is used to find proportional measurements.

proportions means having the same ratio.

scale factor is the ratio of the model measurement to the actual measurement in a simplest form.

or we can say that the ratio of any two corresponding lengths in two similar geometric figures

if the scale factor is more than 1, then it is an enlargement,

if the scale factor less than 1, then it is a reduction.

given the two geometric figure:

by definition of proportions, we have