Three integers sum to 57. The second integer is twice the first integer. The third integer is seven less than five times the first integer. What are the three integers?

a=8

b=16

c=33

Step-by-step explanation:

Let's call the integers a, b, and c. (a is the first, b is the second, and c is the third.)

a+b+c=57

Write the second two sentences as equations.

b=2a

c=5a-7

Plug in these values of b and c to the original equation.

a+(2a)+(5a-7)=57

Solve for a:

a+2a+5a-7=57

8a-7=57

8a=64

a=8

Now, plug in your solution for a into the equations for b and c to solve for them.

b=2a=2(8)=16

c=5a-7=5(8)-7=40-7=33

You can add up your answers for a, b, and c to make sure you're correct.

a+b+c=8+16+33=57

I hope this helped!

450

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