When solving the radical equation 2+2x+11−−−−−−√=x, the values x=−1 and x=7 are obtained. Determine if either of these values is a solution of the radical equation. Select the correct two answers. Since substituting x=−1 into the original equation resulted in a true statement, x=−1 is a solution to this equation. Since substituting x=7 into the original equation resulted in a true statement, x=7 is a solution to this equation.

Since substituting x=7 into the original equation resulted in a false statement, x=7 is a not solution to this equation.

Since substituting x=−1 into the original equation resulted in a false statement, x=−1 is not a solution to this equation.

its 4 because 2 times 2 is 4, if you double the number two you get four

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

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step-by-step explanation:

my best guesses would have to be either 4.5 or 2. p.s. if they're wrong, i'm so sorry for giving you the wrong answer.