Question 8 of 10 What is a point-slope equation of the line with slope -13 that goes through
the point (5, 7)?
A. Y-7 = -13(x - 5)
B. y + 5 = -13(x + 7)
0.000
C. y- 5 = -13(x-7)
D. y + 7 = -13(x + 5)
SUBMIT

A

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

Here m = - 13 and (a, b ) = (5, 7 ) , then

y - 7 = - 13(x - 5) → A

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.

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step-by-step explanation:

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