I only have 30 minutes left can someone explain the answer? ILL MARK BRAINLIEST

i think the answer would be (-2,-50)

Step-by-step explanation:

f(x)=2x^2+8x−42

Locate the vertex of the parabola.

Rewrite the equation in vertex form.

y=2(x+2)^2−50

Use the vertex form,

y=a(x−h)^2+k

to determine the values of a, h and k.

a=2h=−2k=−50

Since the value of a

is positive, the parabola opens up.

Find the vertex

(h,k).(−2,−50)

The range of a parabola that opens up starts at its vertex

(−2,−50)

and extends to infinity.

Interval Notation:[−50,∞)

Set-Builder Notation:

{y|y≥−50}

sine

step-by-step explanation: