Mathematics, 24.11.2021 02:40 achoward08

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form? 7x 2y = –1 7x 2y = 1 14x 4y = –1 14x 4y = 1.

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Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard fo...

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