WILL GIVE BRAINLIEST AND WORTH 20 POINTS! A train leaves Los Angeles at 2 p. m. heading north at 50 mph. If the next train leaves three hours later and also heads north at 60 mph, at what time will the second train catch up with the first?

Well having the given information

2 pm is when the first trian leaves or (a)

5 pm is when the second train leaves (b) since 3 hours later

Now train a travels 50mph

Whilst train b travels 60 mph

Train b is 3 hours behind so a is already at the 150 miles mark.

Now we just find when train B catches up with A

60, 120, 180, 240, 300, 360, 420, 480, 540, 600

150, 200, 250, 300, 350, 400, 450, 500, 550, 600

Well 600  when they meet up at the same time

So in this scenario it’s starting 5pm and there are 10 hours

Now we just add 10 hours to 5pm

3am

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4