a teacher brought to class a pack of notebooks. if her gives his students 5 notebooks to each, he will have 7 notebooks left. if he tries to give each student 7 notebooks, he will be 5 notebooks short. how many students are there in the class?

There are six students in his class

6 students

Step-by-step explanation:

Let the number of notebooks be $x$ and the number of students be $y.$

If there are 5 notebooks per student, we have:

$x-5y=7$

Simliairly, we have 7 notebooks per person, which is:

$x-7y=-5$

Then, using system of equations, we can add multiply the first equation by $-1$ and then add.

We would have:

$-1(x-7y=-5)=-x+7y=5$

Then, adding gives us:

$2y=12$

$y=6$

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.