![f(x)=|-2x+1|\qquad \qquad \stackrel{domain}{\{-2~~,~~1~~,~~\frac{2}{3}\}} \\\\[-0.35em] ~\dotfill\\\\ f(-2)=|-2(-2)+1|\implies f(-2)=|4+1|\implies f(-2)=\boxed{5} \\\\\\ f(1)=|-2(1)+1|\implies f(1)=|-2+1| \\\\\\ \qquad f(1)=|-1|\implies f(1)=\boxed{1}](/tpl/images/2566/4020/40444.png)
![f\left( \frac{2}{3} \right)=\left|-2\left( \frac{2}{3} \right)+1\right|\implies f\left( \frac{2}{3} \right)=\left|-\frac{4}{3}+1\right|\implies f\left( \frac{2}{3} \right)=\left|\frac{-4+3}{3}\right| \\\\\\ \qquad \qquad f\left( \frac{2}{3} \right)=\left|-\frac{1}{3}\right|\implies f\left( \frac{2}{3} \right)=\boxed{\frac{1}{3}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{range}{\{5~~,~~1~~,~~\frac{1}{3}\}}~\hfill](/tpl/images/2566/4020/0773b.png)
Hey everybody!
Could you please try and help me with this?
I would be very grateful if...
Mathematics, 22.11.2021 14:00 rouchedavisin4
Hey everybody!
Could you please try and help me with this?
I would be very grateful if you could!
Answers: 1
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