7. A value of n is substituted in each expression to get the number in the box. Find each value of n.
a) 5n
30
b) 3n – 1 11
c) 4n + 7 15
d) 5n
11
e) 4 + on 40
f) 5 +1 5
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a. n=6

b. n = 4

c. n =2

d. n = 11 ÷ 5

e. n = 10

f. 20

Step-by-step explanation:

a. 5n = 30

n=30÷5

n=6

b. 3n-1 = 11

3n= 11 + 1

n = 12 ÷3

n=4

c. 4n + 7 = 15

4n = 15 - 7

n = 8 ÷ 4

n = 2

d. 5n = 11

n = 11 ÷ 5

e. 4 + n = 40

n = 40 - 4

n = 10

f. 5 + 15 = 20

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step-by-step explanation:

nndncnd cnn

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explanation:

infrared radiation has wavelength in the range between 700 nm and 1 mm. lets' convert these values into scientific notation, keeping in mind that:

let's start from the lower value, we have:

(we moved the dot two places to the left, so we increased the exponent by 2 units, from -9 to -7)

the higher value is:

so, the range of wavelength of infrared radiation is: