Arlington ISD needs to construct a handicap ramp for one of its new buildings under construction. One point on the construction blueprint for the ramp can be identified by the ordered pair (d, 4d), and another point on the ramp is identified by the ordered pair (3d, 5d). If d is not equal to zero, what will the slope of the handicap ramp be after construction is completed?

The slope of the handicap ramp is 1/2

The slope of the handicap ramp is gotten from the equation for the slope of a line, m with endpoints (x₁, y₁) and (x₂, y₂).

m = (y₂ - y₁)/(x₂ - x₁)

Since one point of the ramp can be identified by the ordered pair (d, 4d) and another point on the ramp is identified by the ordered pair (3d, 5d), we have that (x₁, y₁) = (d, 4d) and (x₂, y₂) = (3d, 5d).

Substituting the values of the variables into the equation, we have

m = (y₂ - y₁)/(x₂ - x₁)

m = (5d - 4d)/(3d - d)

m = d/2d

m = 1/2

So, the slope of the handicap ramp is 1/2

Learn more about slope of a line here:

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: