Find the perimeter. Simplify your answer.

6z-30 :D

Step-by-step explanation:

Step-by-step explanation:

The perimeter of a square is just all the sides added up together. To do this we can make an equation.

2(z-5) + 2(2z - 10)

This represents two sides with different lengths two times. To solve, you first use the distributive property to multiply z-5 by 2.

2z - 10 + 2(2z - 10)

We then use the distributive property by multiplying 2z - 10 by 2.

2z − 10 + 4z − 20

We then combine 2z and 4z to get 6z.

6z − 10 − 20

Subtract 20 from 10 to get -30.

6z-30.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

its an acute right triangle

step-by-step explanation: