subject
Mathematics, 11.11.2021 09:50 jahi1201

3 2
+
(
βˆ’
k
)
+
(
βˆ’
2
)
2
3

+(βˆ’k)+(βˆ’2)start fraction, 3, divided by, 2, end fraction, plus, left parenthesis, minus, k, right parenthesis, plus, left parenthesis, minus, 2, right parenthesis where
k
=
βˆ’
5
2
k=βˆ’
2
5

k, equals, minus, start fraction, 5, divided by, 2, end fraction.

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3 2
+
(
βˆ’
k
)
+
(
βˆ’
2
)
2
...
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