Please help, Can’t find the answer anywhere
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Mathematics, 11.11.2021 01:50 damianfrasieanu5387
Please help, Can’t find the answer anywhere
Answers: 1
Mathematics, 21.06.2019 13:40
Vip at (-2,7) dropped her pass and moved to the right on a slope of -9 where can you catch up to her to return her vip pass
Answers: 1
Mathematics, 21.06.2019 22:00
For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠ [tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠ ± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]
Answers: 2
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