Giải phương trình sai phân: y(n) - 4y(n - 2) = 2x(n) + 3x(n - 2)
y(n) = o khi n < 0, x(n) = 5×2^(n)

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

i use my brain for prombles like this maybe you could try it

step-by-step explanation:

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: