Givenf(x)=x3−6x2−11x+6f(x)=x3−6x2−1 1x+6 Find f(2). (a) -40. (b) 40. (c)32. (d)-32

f(2) = -32

Step-by-step explanation:

f(x) = x^3 − 6x^2 − 11x + 6

f(2) = 2^3 - 6(2)^2 - 11(2) + 6

f(2) = 8 - 24 - 22 + 6

f(2) = -32

side xy = 10

sin(x) = 4/5

cos(x) = 3/5

tan(x) = 4/3

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet