Answer please/

Coordinate of B: (3, -5)

Coordinate of C: (3, 5)

Coordinate of D: (0, -1)

Step-by-step explanation:

Point A is (-2, -5).

The distance between line AB is 5 units.

The distance between line BC is 10 units.

To find the point for B, the distance is 5 units on the x axis.

The x point for point B is -2 + 5 which is 3 units. x = 3

The y point doesn't change, so the coordinate of point B is (3, -5).

The distance between line BC is 10 units.

To find the point of C, the distance is 10 unites on the y axis.

The y point for point b is -5 + 10 which is 5 units. y = 5

The x point doesn't change, so the coordinate of point C is (3, 5).

We find an equation for line AC. The equation is y = mx + b.

Y is any y point on the line. X is any x point on the line. M is the slope of the line. B is the y-intercept of the line.

Since D is right on the y axis, this means that the x point of D is 0.

Point C is (3, 5) and point A is (-2, -5).

We use (y2 - y1) / (x2 - x1) and substitute. Y is the y point and x is the x point.

(5 - (-5)) / (3 - (-2)) = 10 / 5 = 2

The slope of the line is 2.

With this, we get the equation of y = 2x + b

We insert one of the random x point and y point which (in this case) I choose (3, 5).

Substituting, we get -

5 = 2 * 3 + b

5 = 6 + b

b = 5 - 6

b = -1

So the y-intercept of the graph is -1 and for the graph, we get -

y = 2x - 1

D is already the line of the y-intercept, but we can make sure by inserting the x point as 0.

y = 2 * 0 - 1

y = 0 - 1

y = -1

The coordinate of point D is (0, -1).

too hard the other guy did it

step-by-step explanation: