The sum of three integers is 12. The sum of the first and second integers exceeds the third by 32. The third integer is 15 less than the first. Find the three integers.

Step-by-step explanation:

So we know the sum of three integers is 12

x+y+z=12

Next we know that the sum of the first and second integer is more than the third by 32

x+y=z+32

Finnaly, we can see that the third is 15 less than the first.

x-15=z

Now time to put it all together.

x+(x-15+32-x)+(x-15)=12

2x-15-15+32=12

2x-30+32=12

2x+2=12

2x=14

x=7

Now time to plug it all in

7 also known as x minus 15 = z

7-15=-8

z=-8

Next we can plug it in the first equation.

7+y-8=12

-1+y=12

y=11

Now time to check if I am correct(spoiler, if it's posted it means I am correct :D)

x=7,y=11,z=-8

7+11-8=12

Yay there is ur answer.

First Integer Is 7, 2nd is 11, third is -8

P.S. Sorry if it is correct, my first answer.

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".