Help please im so close

B. -7.25

Step-by-step explanation:

On a number line, if there is one bar between 1 and 2, that bar is 1.5. If there are 3 bars between 1 and 2, the three bars from left to right are 1.25, 1.5, and 1.75. Using this knowledge, your answer would be -7.25. A picture is attached for further clarity.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.