1.An equation of a line passing through the point ( 3, 0 ) with a slope of 1 is * A y = x + 3
B y - x = 3
C y = x - 3
D y - 3 = x

2.The line y = 2x - 8 cuts the x -axis at the point R. What are the coordinates of R? *

A ( 4, 0)
B ( -4, 0)
C ( -8, 0)
D (0, 8)

1) if to substitute the given coordinates and slope into the common form of equation (it is y=s*x+i), then 0=3*1+i, ⇒ i= -3. The required equation is y=x-3.

C. y=x-3.

2) according to the condition coordinates of R are (x;0). Then it is possible to calculate the x-coordinate of R after substitution into the slope-interception form (it is y=s*x+i): 0=2x-8; ⇒ x=4. The coordinates of R are (4;0).

A. (4;0).

i believe

step-by-step explanation:

from my conclusion c

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation: