The equation of straight line is 3x+2y=6 a) write down the gradient of this line
b) write down the coordinates of the point where the line crosses the y-axis.

gradient = - , y- intercept = (0, 3 )

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the gradient and c the y- intercept )

Given

3x + 2y = 6 ( subtract 3x from both sides )

2y = - 3x + 6 ( divide terms by 2 )

y = - x + 3 ← in slope- intercept form

with gradient m = - and y- intercept c = 3 ⇒ (0, 3 )

answer: a and c are correct

step-by-step explanation:

the +5 is the vertical translation

the added negative symbol in front is the reflection over the y-axis

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.