PLEASE I NEEED IT RN

2x2+9x=x−368=0

2x2+9x−(x−368)=0

2x2+9x−x+368=0

2x2+8x+368=0

2(x2+4x+184)=0

=

−±2−4√2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2+4+

18

4=0

x^{2}+4x+184=0

x2+4x+184=0

=1

a={\color{#c92786}{1}}

a=1

=4

b={\color{#e8710a}{4}}

b=4=

184

c={\color{#129eaf}{184}}

c=184

=−4±42−4⋅1⋅184√2⋅1

Multiply the numbers

Subtract the numbers

Multiply the numbers

=−4±−720√2

Step-by-step explanation:

here is your answer hope you will enjoy and mark me as brainlist

thank you

33/100 is what i got

yep b and c r the correct got it! : )