Help, please Exercise #4: Consider the equation 7x+2(x+5)=9x +10.
(a) Show that x=-5 and x=2 are both solutions to this equation.
(b) Solve this equation by manipulating each side of the equation as we did above. What does its final "strang result tell you?
(c) Test your conclusion in (b) by picking a random integer (or really any number) and showing that it is a solution
to the equation

Please help algebra class

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

are ya tryin to ask something or is this a statement