The Hoover Dam backs up the Colorado River and creates Lake Mead, which is approximately 115 miles long and has a surface area of approximately 225 square miles. If during flood conditions, the Colorado River flows into the lake at a rate of 45,000 cfs and the outflow from the dam is 8,000 ft3/s, how many feet per 24-hour day will the lake level rise

9514 1404 393

  0.510 ft per 24-hour period

Step-by-step explanation:

We can first find the change in volume in a day:

  (45,000 cfs -8,000 cfs)×(3600 s/h)×(24 h/day) = 3.1968×10^9 ft³/day

The area in square feet is about ...

  (225 mi²)×(5280 ft/mi)² = 6.27264×10^9 ft²

Then the rate of change of height is ...

  h' = ΔV/A = (3.1968×10^9 ft³/day)/(6.27264×10^9 ft²) ≈ 0.510 ft/day

For the given flows, the lake level will rise about 0.510 feet per day.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

answer: you need the equation in the question so i can answer it

step-by-step explanation: