Uhmm guys I need friends
...
Answers: 1
Another question on Mathematics
Mathematics, 21.06.2019 22:00
For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠[tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]
Answers: 2
Mathematics, 22.06.2019 03:50
The image of abc is a'b'c. what transformations would result in this image? abc is reflected over the line x = 1, then is rotated -90° around the origin. abc is reflected over the line y = x - 1, then t: (x, y) → (x - 1, y - 1). abc is rotated 90° around the origin, then is reflected over the y-axis. abc is rotated -90° around the origin, then is reflected over the line y = -1.
Answers: 2
You know the right answer?
Questions
Business, 29.01.2020 00:51
Mathematics, 29.01.2020 00:51
Social Studies, 29.01.2020 00:51
Mathematics, 29.01.2020 00:51
Mathematics, 29.01.2020 00:51
Chemistry, 29.01.2020 00:51
Mathematics, 29.01.2020 00:51
