(( BRAINLISET QUEATION )) The temperature of a room is -4 degree Celsius. The temperature of the heater is 16 degree Celsius. How many degrees more than room temperature is the heater?

Step-by-step explanation:

Under steady state condition heat released to the room=heat dissipated out of the room Let θ be the temperature of heater Then

θ−20=α[20−(−20)] .(i)

and θ−10=α[10−(−40)] .(ii) Solving Eqs. (i) and (ii) we get

we get

θ=60∘C

y > 1/3x

y < = -x + 4

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