The diagonals of a rhombus measure 16 cm and 30 cm .find its perimeter ( in easy way)?

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Step-by-step explanation:

Let ABCD be a rhombus, all sides of the rhombus have equal length and its diagonal AC and BD are intersecting each other at a point O.

As we know that the diagonals in the rhombus bisect each other at 90°.

So, AO can be written as (AC/2)  

= 16/2  

= 8 cm

And, DO can be written as (BD/2)

= 30/2  

= 15 cm

Then, consider the triangle AOD and apply Pythagoras theorem,  

AD2 = AO2 + DO2

AD2 = 82 + 152

AD2 = 64 + 225

AD2 = 289

AD = √289

AD = 17 cm

Hence, the length of each side of the rhombus is 17 cm

Now,

The perimeter of rhombus = 4 × side of the rhombus

= 4 × 17

= 68 cm

Therefore, the perimeter of the rhombus is 68 cm.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

75

step-by-step explanation: