The diagonals of a rhombus measure 16 cm and 30 cm .find its perimeter ( in easy way)?

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Step-by-step explanation:

Let ABCD be a rhombus, all sides of the rhombus have equal length and its diagonal AC and BD are intersecting each other at a point O.

As we know that the diagonals in the rhombus bisect each other at 90°.

So, AO can be written as (AC/2)  

= 16/2  

= 8 cm

And, DO can be written as (BD/2)

= 30/2  

= 15 cm

Then, consider the triangle AOD and apply Pythagoras theorem,  

AD2 = AO2 + DO2

AD2 = 82 + 152

AD2 = 64 + 225

AD2 = 289

AD = √289

AD = 17 cm

Hence, the length of each side of the rhombus is 17 cm

Now,

The perimeter of rhombus = 4 × side of the rhombus

= 4 × 17

= 68 cm

Therefore, the perimeter of the rhombus is 68 cm.

im pretty sure its

(8,15)

step-by-step explanation:

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: