Find f(0) and f(6)

f(x)= x^2+10x+72/x^2-12x+36

f(0) = 2     f(5) = 147

Step-by-step explanation:

f(0) = (0²+10·0+72)/(0²-12·0 + 36)   Substitute 0 for x and solve.

      = 72/36

       = 2

f(5) = (5²+10·5+72)/(5²-12·5 + 36)      Substitute 5 for x and solve.

     = (25 + 50 + 72)/(25 - 60 +36)

     = 147/1

      = 147

it's

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong