A 4 in. by 5 in. photo is enlarged so that its width (shorter dimension) is 5 in. What is the length of the enlarged photo?

5.25 in.

7 in.

6.25 in.

6 in.

Explanation:

The jump from 4 inches to 5 inches is 5/4 = 1.25

In other words, 4*1.25 = 5

So we need to multiply every dimension by the scale factor 1.25 to enlarge the image. The 5 inch dimension then goes to 5*1.25 = 6.25 inches

Here's another way you can solve

(old width)/(old length) = (new width)/(new length)

4/5 = 5/x

4x = 5*5

4x = 25

x = 25/4

x = 6.25

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

its a straight line parallel to the time axis