In ΔHIJ, \text{m}\angle H = (x-1)^{\circ}m∠H=(x−1)
∘
, \text{m}\angle I = (2x+5)^{\circ}m∠I=...
Mathematics, 25.10.2021 09:50 AM28
In ΔHIJ, \text{m}\angle H = (x-1)^{\circ}m∠H=(x−1)
∘
, \text{m}\angle I = (2x+5)^{\circ}m∠I=(2x+5)
∘
, and \text{m}\angle J = (7x+6)^{\circ}m∠J=(7x+6)
∘
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