Andre’s group was asked to write an expression equivalent to 5 p squared q + 7 p q squared minus 10. When Ms Berger checked their answers, she found only one to be correct. Who had the correct answer? Andre’s Group
Student
Equivalent Expression
Andre
7 p squared q + 7 p q squared minus 1 minus 2 p squared q minus 9
Jill
5 p squared q + 2 p q squared minus 6 + 5 p q squared minus 3
Anuj
4 p squared q + 7 p q squared minus 7 + 2 p squared q minus 3
Marsha
5 p squared q + 5 p q squared minus 10 + 3 p q squared

Math it's appreciated. (picture provided)

Each of the following data sets has a mean of x = 10. (i) 8 9 10 11 12 (ii) 7 9 10 11 13 (iii) 7 8 10 12 13 (a) without doing any computations, order the data sets according to increasing value of standard deviations. (i), (iii), (ii) (ii), (i), (iii) (iii), (i), (ii) (iii), (ii), (i) (i), (ii), (iii) (ii), (iii), (i) (b) why do you expect the difference in standard deviations between data sets (i) and (ii) to be greater than the difference in standard deviations between data sets (ii) and (iii)? hint: consider how much the data in the respective sets differ from the mean. the data change between data sets (i) and (ii) increased the squared difference îł(x - x)2 by more than data sets (ii) and (iii). the data change between data sets (ii) and (iii) increased the squared difference îł(x - x)2 by more than data sets (i) and (ii). the data change between data sets (i) and (ii) decreased the squared difference îł(x - x)2 by more than data sets (ii) and (iii). none of the above

20 points + brainliest answer + my mom’s chocolate chip cookie ! subtract.