The sum of two consecutive odd numbers is 1408. What are the numbers? Put the smaller number first comma then the larger number.

703,705

Step-by-step explanation:

divide 1408 by 2

add one for one number

subtract one for the other

x = 1st odd number. x + 2 = 2nd odd number. Now we know their "sum" is 148. So when we add them together we get 148: 1st odd number + 2nd ...

Step-by-step explanation:

where is the rest of the

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.