Please please help me with this question please help me now please

a) linear, straight when graphed and no exponents

b) quadratic, x has exponent

c) quadratic, x has exponent

d) linear, no exponent

e) quadratic, x has exponent

f) i think it's neither because there's two variables that can't add together

Step-by-step explanation:

A is linear because a linear equation is mapped in the form y=ax+b and results in a straight line when graphed. This equation has a slope, 1, which occupies the space for a and a y-intercept of 3 which occupies the space for b

B is neither because it doesn't fit the linear form or the quadratic form (which is constrained by the equation y=ax^2+bx+c. The highest degree for this form is 2.) I believe this function is actually a type of cubic which is not an option for the question.

C is a quadratic because it follows the form y=ax^2+bx+c and results in a parabola

d. 3x-y=5 is linear because even though it is not in the y=ax+b form, it can be manipulated into it by subtracting 3x from both sides and then dividing by -1 on both sides to get y=3x-5 which fits the form and graphs a line.

e. 5-x^2=89 would be neither because there is only one variable and there is no value of y that can be solved for. While we can find an x value (or perhaps multiple x values depending on the equation) it wouldn't result in a graphable equation which is a necessity to be classified as a linear or quadratic. In fact, I believe this is actually just an equation and not a function at all and since linear and quadratics are forms of functions they cannot be either. This is because a function is defined as a relation between two variables where each input has one (and only one) output and this equation doesn't have two variables and wouldn't have an output.

f. Neither for the same reason as in e

Hope this helps!

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation: