Mathematics, 20.10.2021 01:00 toomuch94
A company has $8,970 available per month for advertising. Newspaper ads cost $200 each and can't
run more than 19 times per month. Radio ads cost $470 each and can't run more than 28 times per
month at this price.
Each newspaper ad reaches 5800 potential customers, and each radio ad reaches 7100 potential
customers. The company wants to maximize the number of ad exposures to potential customers.
Use n for number of Newspaper advertisements and r for number of Radio advertisements.
Maximize P =
subject to
< 19
< 28
< $8,970
Enter the solution below. If needed, round ads to 1 decimal palace and group exposure to the
nearest whole person.
Number of Newspaper ads to run is
Number of Radio ads to run is
Maximum target group exposure is
people
Answers: 3
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A company has $8,970 available per month for advertising. Newspaper ads cost $200 each and can't
r...
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