You have a deck of cards and select two cards randomly, without replacing the first
card before selecting the second one. What
are the odds that you've selected the 3 of
Clubs and the 4 of Hearts?

Step-by-step explanation:

Total cards are 52

Number of King cards = 4

Probability of selecting a King first = 4/52 = 1/13

Cards left = 51

Number of Queen cards = 4

Probability of selecting a Queen = 4/51

Probability of drawing a king first and then a queen = (1/13) X (4/51) = 4/663 = 0.6%

Hope I have explained it in the simplest possible way.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

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