first we draw the graph of both function using t-table method
equation: x+y> 5
for x=0, y=5
for x=-5, y=0
table:
x : 0 5
y : 5 0
test point (0,0) , 0> 5
false
equation: -3x+2y< -2
for x=0, y=-1
for x=2, y=4
table:
x : 0 2
y : -1 4
test point (0,0) , 0< -2
true
now we draw the graph. see the attachment for graph.
common region would be solution set.
option 2 is correct.
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Mathematics, 21.06.2019 22:10
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